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x^2-36x-308=+
We move all terms to the left:
x^2-36x-308-(+)=0
We add all the numbers together, and all the variables
x^2-36x-308-0=0
We add all the numbers together, and all the variables
x^2-36x-308=0
a = 1; b = -36; c = -308;
Δ = b2-4ac
Δ = -362-4·1·(-308)
Δ = 2528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2528}=\sqrt{16*158}=\sqrt{16}*\sqrt{158}=4\sqrt{158}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-4\sqrt{158}}{2*1}=\frac{36-4\sqrt{158}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+4\sqrt{158}}{2*1}=\frac{36+4\sqrt{158}}{2} $
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